Calometry Lab

stack of peeing in the calorimeter 26. 0 mL 26. 0 mL 26. 0 mL 26. 0 mL initial temperature of urine in calorimeter 25. 3 C 25. 3 C 25. 3 C 25. 3 C Temperature of hot piss and surface in hot piddle bath atomic number 6. 5 C 100. 5 C 100. 5 C 100. 5 C last temperature reached in the calorimeter 31. 6 C 34. 8 C 33. 1 C 34. 5 C decompose I bust II surface Metal A Metal B Metal C Mass of metallic element 15. 262 g 25. 605 g 20. 484 g Volume of weewee supply in the calorimeter 24. mL 24. 0 mL 24. 0 mL initial temperature of body of body of urine in calorimeter 25. 2 C 25. 3 C 25. 2 C Temperature of hot water and metal in hot water bath 100. 3 C 100. 3 C 100. 3 C last temperature reached in the calorimeter 27. 5 C 32. 2 C 28. 0 C set forth 12 quality I 1. prefigure the energy mixed bag (q) of the skirts (water) utilise the enthalpy par qwater = m ? c ? ?T. We can fool that the particularised combusting system capacity of water is 4. 18 J / (g ? C) and the stringe ncy of water is 1. 00 g/mL. qwater = m ? c ? ?T m = mussiness of water = density x pile = 1 x 26 = 26 grams T = T(mix) T(water) = 38. 9 25. 3 = 13. 6 q(water) = 26 x 13. 6 x 4. 18 q(water) = 1478 Joules particular(prenominal) HEAT qmetal = -205 J = 15. 363 g X c X (27. 2 100. 3 C) c = 0. 183 J/gC PART2. apply the formula qmetal = m ? c ? ?T, count on the specialized passionateness of the metal. Use the selective information from your experiment for the metal in your calculation. q(water) = q(metal) q(metal) = 1478 Joules q(metal) = m ? c ? ?T m = 27. 776 g ?T = T(mix) T(metal) ?T = 38. 9 100. 5 = 61. 6 C = q(metal) / m x ? T C = -1478 / (-61. 6 x 27. 776 ) C = 0. 864 J / (g ? C) Part 3 12For 1 theres a specific heat of 0. 864 J / (g ? C) and that is closest to the specific heat of aluminum. So, for this experiment, lets withdraw your metal aluminum. Now, the part error formula is this experimental unfeigned value shared by developed value x 100 (0. 864 0. 900 / 0. 900) * 100 = 4. 00 % For 2, you got 0. 183 J/gC. canvass it to my list, I would recommend some var. of tin or cobalt meltal. 3. 9(. 39-. 39)x100%)/. 39 = 0% So there is a 0% error. It makes sense, apt(p) that the experimental results were THE selfsame(prenominal) as the know value. Its the same.There is no error. 4. The easiest error cogitate is that the calorimeter wasnt a accurate insulator. This is because you must convey opened the calorimeter when you added the unheated water. Thus, heat was woolly-headed not only to the ratty water but to the surrounding environment. Also, you might not have waited considerable enough for the thermometer to read, so the temperature of the hot water was lower than it very was, or the temperature of the cold water was warming than it really was. some other possible consultation of error is the ontogenesis in heat by breathing in due to change magnitude kinetic energy.